5x^2-6x-232=0

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Solution for 5x^2-6x-232=0 equation:



5x^2-6x-232=0
a = 5; b = -6; c = -232;
Δ = b2-4ac
Δ = -62-4·5·(-232)
Δ = 4676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{4676}=\sqrt{4*1169}=\sqrt{4}*\sqrt{1169}=2\sqrt{1169}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{1169}}{2*5}=\frac{6-2\sqrt{1169}}{10} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{1169}}{2*5}=\frac{6+2\sqrt{1169}}{10} $

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